Termination w.r.t. Q of the following Term Rewriting System could not be shown:
Q restricted rewrite system:
The TRS R consists of the following rules:
h2(x, y) -> f3(x, y, x)
f3(0, 1, x) -> h2(x, x)
g2(x, y) -> x
g2(x, y) -> y
Q is empty.
↳ QTRS
↳ DependencyPairsProof
Q restricted rewrite system:
The TRS R consists of the following rules:
h2(x, y) -> f3(x, y, x)
f3(0, 1, x) -> h2(x, x)
g2(x, y) -> x
g2(x, y) -> y
Q is empty.
Q DP problem:
The TRS P consists of the following rules:
F3(0, 1, x) -> H2(x, x)
H2(x, y) -> F3(x, y, x)
The TRS R consists of the following rules:
h2(x, y) -> f3(x, y, x)
f3(0, 1, x) -> h2(x, x)
g2(x, y) -> x
g2(x, y) -> y
Q is empty.
We have to consider all minimal (P,Q,R)-chains.
↳ QTRS
↳ DependencyPairsProof
↳ QDP
Q DP problem:
The TRS P consists of the following rules:
F3(0, 1, x) -> H2(x, x)
H2(x, y) -> F3(x, y, x)
The TRS R consists of the following rules:
h2(x, y) -> f3(x, y, x)
f3(0, 1, x) -> h2(x, x)
g2(x, y) -> x
g2(x, y) -> y
Q is empty.
We have to consider all minimal (P,Q,R)-chains.